What is the answer to (x+4)/(4x+7)=(x-3)/(x^2-x-6) ?

The answer to (x+4)/(4x+7)=(x-3)/(x^2-x-6) is x=-1

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(x+4)/(4x+7)=(x-3)/(x^2-x-6)

\frac{x + 4}{4 x + 7} = \frac{x - 3}{x ^{2} - x - 6}

x = - 1

Solution steps

\frac{x + 4}{4 x + 7} = \frac{x - 3}{x ^{2} - x - 6}

Cross multiply

(x + 4) (x + 2) = 4 x + 7

Solve

(x + 4) (x + 2) = 4 x + 7 : x = - 1

x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - \frac{7}{4}, x = - 2, x = 3

Combine undefined points with solutions:

x = - 1

\frac{3 x - 1}{6 x - 2} = \frac{2 x + 5}{4 x - 13}

\frac{3 a}{x} - \frac{2 x}{a} = 1

\frac{2.5}{35} = \frac{2}{d}

\frac{x - 4}{x - 1} = \frac{12}{3 - x} + 1

0 = 2 x - \frac{128}{x ^{2}}

What is the answer to (x+4)/(4x+7)=(x-3)/(x^2-x-6) ?
The answer to (x+4)/(4x+7)=(x-3)/(x^2-x-6) is x=-1
Solve for x: (x+4)/(4x+7)=(x-3)/(x^2-x-6)
The solution is x=-1