What are the solutions to the equation 2x^2-13x=7 ?

The solutions to the equation 2x^2-13x=7 are x=7,x=-1/2

Find the zeros of 2x^2-13x=7

The zeros of 2x^2-13x=7 are x=7,x=-1/2

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2 x^{2} - 13 x = 7

x = 7, x = - \frac{1}{2}

Decimal Notation

x = 7, x = - 0.5

Solution steps

2 x^{2} - 13 x = 7

Move

7

to the left side

2 x^{2} - 13 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 (- 7) = 15

x_{1, 2} = \frac{- ( - 13 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 15}{2 \cdot 2}

x = \frac{- ( - 13 ) + 15}{2 \cdot 2} : 7

x = \frac{- ( - 13 ) - 15}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{1}{2}

(\frac{1}{2} + \frac{3}{2} i)^{6}

10 x^{2} - 20 x - 10 = 0

(- \frac{4}{7})^{4}

a^{- 3}

8 x - 4 = 2 (3 x + 6)

What are the solutions to the equation 2x^2-13x=7 ?
The solutions to the equation 2x^2-13x=7 are x=7,x=-1/2
Find the zeros of 2x^2-13x=7
The zeros of 2x^2-13x=7 are x=7,x=-1/2