What is the answer to 1/(x^2-8x)+(6x)/(x-8)=-1 ?

The answer to 1/(x^2-8x)+(6x)/(x-8)=-1 is x=1,x= 1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(x^2-8x)+(6x)/(x-8)=-1

\frac{1}{x ^{2} - 8 x} + \frac{6 x}{x - 8} = - 1

x = 1, x = \frac{1}{7}

Decimal Notation

x = 1, x = 0.14285 \dots

Solution steps

\frac{1}{x ^{2} - 8 x} + \frac{6 x}{x - 8} = - 1

Multiply by LCM

1 + 6 x^{2} = - x (x - 8)

Solve

1 + 6 x^{2} = - x (x - 8) : x = 1, x = \frac{1}{7}

x = 1, x = \frac{1}{7}

Verify Solutions

Find undefined (singularity) points:

x = 8, x = 0

Combine undefined points with solutions:

x = 1, x = \frac{1}{7}

\frac{1}{x} + \frac{1}{x + 5} = \frac{1}{6}

\frac{600}{300 + x} = \frac{400}{300 - x}

\frac{3}{4 ( 2 x - 3 )} = 1

1 - \frac{3}{x} = 0

b, \frac{d}{b} = (\frac{n}{q})^{3}

What is the answer to 1/(x^2-8x)+(6x)/(x-8)=-1 ?
The answer to 1/(x^2-8x)+(6x)/(x-8)=-1 is x=1,x= 1/7
Solve for x: 1/(x^2-8x)+(6x)/(x-8)=-1
The solution is x=1,x= 1/7