What is the answer to (x-1}{x+1}-\frac{3+x)/x =2 ?

The answer to (x-1}{x+1}-\frac{3+x)/x =2 is x=-1/2 ,x=-3

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(x-1}{x+1}-\frac{3+x)/x =2

\frac{x - 1}{x + 1} - \frac{3 + x}{x} = 2

x = - \frac{1}{2}, x = - 3

Decimal Notation

x = - 0.5, x = - 3

Solution steps

\frac{x - 1}{x + 1} - \frac{3 + x}{x} = 2

Multiply by LCM

x (x - 1) - (3 + x) (x + 1) = 2 x (x + 1)

Solve

x (x - 1) - (3 + x) (x + 1) = 2 x (x + 1) : x = - \frac{1}{2}, x = - 3

x = - \frac{1}{2}, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Combine undefined points with solutions:

x = - \frac{1}{2}, x = - 3

- 1 = \frac{x ^{2} + 1}{x - 3}

\frac{1}{x} + 2 = \frac{1}{x ^{2} + x}

\frac{6 - 5 + 14}{n \cdot 2} = 15

\frac{5}{3 x - 8} = - 1

q + \frac{9}{q} = - 10

What is the answer to (x-1}{x+1}-\frac{3+x)/x =2 ?
The answer to (x-1}{x+1}-\frac{3+x)/x =2 is x=-1/2 ,x=-3
Solve for x: (x-1}{x+1}-\frac{3+x)/x =2
The solution is x=-1/2 ,x=-3