What is the answer to 4^x+2^{1+2x}=50 ?

The answer to 4^x+2^{1+2x}=50 is x=(ln(50/3))/(2ln(2))

Solve for x: 4^x+2^{1+2x}=50

The solution is x=(ln(50/3))/(2ln(2))

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4^{x} + 2^{1 + 2 x} = 50

x = \frac{ln ( \frac{50}{3} )}{2 ln ( 2 )}

Decimal Notation

x = 2.02944 \dots

Solution steps

4^{x} + 2^{1 + 2 x} = 50

Apply exponent rules

2 x ln (2) = ln (\frac{50}{3})

Solve

2 x ln (2) = ln (\frac{50}{3}) : x = \frac{ln ( \frac{50}{3} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{50}{3} )}{2 ln ( 2 )}

1 0^{- 2 x + 3} = 100

4 x^{3} e^{- 3 x} - 3 x^{4} e^{- 3 x} = 0

4 + 7 e^{- 2 x} = 3 e^{2 x}

x, e^{\frac{x}{y}} = x - y

3^{2 x} + 2 \cdot 3^{x + 1} = 16

What is the answer to 4^x+2^{1+2x}=50 ?
The answer to 4^x+2^{1+2x}=50 is x=(ln(50/3))/(2ln(2))
Solve for x: 4^x+2^{1+2x}=50
The solution is x=(ln(50/3))/(2ln(2))