What is the answer to (4^{x+1})/(2^{x+2)}=186 ?

The answer to (4^{x+1})/(2^{x+2)}=186 is x=(ln(186))/(ln(2))

Solve for x: (4^{x+1})/(2^{x+2)}=186

The solution is x=(ln(186))/(ln(2))

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\frac{4 ^{x + 1}}{2 ^{x + 2}} = 186

x = \frac{ln ( 186 )}{ln ( 2 )}

Decimal Notation

x = 7.53915 \dots

Solution steps

\frac{4 ^{x + 1}}{2 ^{x + 2}} = 186

Apply exponent rules

(2 (x + 1) - x - 2) ln (2) = ln (186)

Solve

(2 (x + 1) - x - 2) ln (2) = ln (186) : x = \frac{ln ( 186 )}{ln ( 2 )}

x = \frac{ln ( 186 )}{ln ( 2 )}

Verify Solutions:

x = \frac{ln ( 186 )}{ln ( 2 )}

True

The solution is

x = \frac{ln ( 186 )}{ln ( 2 )}

e^{a x}

2^{x + 1} - 2^{- x + 2} = 7

4^{3 x - 2} = 1

7^{x} = 4^{2 x - 1}

(\frac{1}{3})^{x + 3} = 3^{8 x + 5}

What is the answer to (4^{x+1})/(2^{x+2)}=186 ?
The answer to (4^{x+1})/(2^{x+2)}=186 is x=(ln(186))/(ln(2))
Solve for x: (4^{x+1})/(2^{x+2)}=186
The solution is x=(ln(186))/(ln(2))