What is the answer to 5^{x+1}+5^x+5^{x-1}= 31/5 ?

The answer to 5^{x+1}+5^x+5^{x-1}= 31/5 is x=0

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5^{x+1}+5^x+5^{x-1}= 31/5

5^{x + 1} + 5^{x} + 5^{x - 1} = \frac{31}{5}

x = 0

Solution steps

5^{x + 1} + 5^{x} + 5^{x - 1} = \frac{31}{5}

Factor

5^{x + 1} + 5^{x} + 5^{x - 1} : 31 \cdot 5^{x - 1}

31 \cdot 5^{x - 1} = \frac{31}{5}

Divide both sides by

31

5^{x - 1} = \frac{1}{5}

Apply exponent rules

x - 1 = - 1

Solve

x - 1 = - 1 : x = 0

x = 0

8^{2 - x} = 2

2 7^{x} - 9^{x + 0.5} - 3^{x} + 3 = 0

2. 5^{2 - 3 x} = 0.1 6^{2 x}

x^{5} = 9^{x}

6 e^{x} - 4 e^{- x} = 5

What is the answer to 5^{x+1}+5^x+5^{x-1}= 31/5 ?
The answer to 5^{x+1}+5^x+5^{x-1}= 31/5 is x=0
Solve for x: 5^{x+1}+5^x+5^{x-1}= 31/5
The solution is x=0