What is the answer to 5^{2x-3}=3^{3x+4} ?

The answer to 5^{2x-3}=3^{3x+4} is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))

Solve for x: 5^{2x-3}=3^{3x+4}

The solution is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))

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5^{2 x - 3} = 3^{3 x + 4}

x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

Decimal Notation

x = - 119.83677 \dots

Solution steps

5^{2 x - 3} = 3^{3 x + 4}

Apply exponent rules

(2 x - 3) ln (5) = (3 x + 4) ln (3)

Solve

(2 x - 3) ln (5) = (3 x + 4) ln (3) : x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

2 x e^{x^{2}} = 0

4^{x^{2} + 2} - 9 \cdot 2^{x^{2} + 2} + 8 = 0

5^{3 x} = 33 (7^{x})

3^{x} + x = 30

x e^{2 x} - x e^{x} - 6 x = 0

What is the answer to 5^{2x-3}=3^{3x+4} ?
The answer to 5^{2x-3}=3^{3x+4} is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))
Solve for x: 5^{2x-3}=3^{3x+4}
The solution is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))