What is the answer to 3^{x-4}=8^{2x+2} ?

The answer to 3^{x-4}=8^{2x+2} is x=(2ln(72))/(ln(3)-6ln(2))

Solve for x: 3^{x-4}=8^{2x+2}

The solution is x=(2ln(72))/(ln(3)-6ln(2))

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3^{x - 4} = 8^{2 x + 2}

x = \frac{2 ln ( 72 )}{ln ( 3 ) - 6 ln ( 2 )}

Decimal Notation

x = - 2.79495 \dots

Solution steps

3^{x - 4} = 8^{2 x + 2}

Apply exponent rules

(x - 4) ln (3) = (2 x + 2) ln (8)

Solve

(x - 4) ln (3) = (2 x + 2) ln (8) : x = \frac{2 ln ( 72 )}{ln ( 3 ) - 6 ln ( 2 )}

x = \frac{2 ln ( 72 )}{ln ( 3 ) - 6 ln ( 2 )}

2 - 3^{- x} + 3^{x + 1} = 0

4 9^{x} = 34 3^{2 x - 3}

3^{x} - \frac{4}{3 ^{x}} = 3

(\frac{1}{2})^{2 x} = 2^{3 - x}

2^{4 x - 3} = 3^{2 - x}

What is the answer to 3^{x-4}=8^{2x+2} ?
The answer to 3^{x-4}=8^{2x+2} is x=(2ln(72))/(ln(3)-6ln(2))
Solve for x: 3^{x-4}=8^{2x+2}
The solution is x=(2ln(72))/(ln(3)-6ln(2))