What is the answer to sqrt(3)^{sqrt(20-\sqrt{x)}}=9 ?

The answer to sqrt(3)^{sqrt(20-\sqrt{x)}}=9 is x=16

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sqrt(3)^{sqrt(20-\sqrt{x)}}=9

3^{20 - x} = 9

x = 16

Solution steps

(3)^{20 - x} = 9

Apply exponent rules

\frac{1}{2} 20 - x = 2

Solve

\frac{1}{2} 20 - x = 2 : x = 16

x = 16

5 \times 2^{x + 1} = 15

t, A = P e^{r t}

(- 1)^{2 x} = 1

(\frac{3}{5})^{x + 1} = \frac{25}{9}

(\frac{1}{4})^{x - 2} = 16

What is the answer to sqrt(3)^{sqrt(20-\sqrt{x)}}=9 ?
The answer to sqrt(3)^{sqrt(20-\sqrt{x)}}=9 is x=16
Solve for x: sqrt(3)^{sqrt(20-\sqrt{x)}}=9
The solution is x=16