What is the answer to 2^{x+1}+2^{x-1}= 5/2 ?

The answer to 2^{x+1}+2^{x-1}= 5/2 is x=0

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2^{x+1}+2^{x-1}= 5/2

2^{x + 1} + 2^{x - 1} = \frac{5}{2}

x = 0

Solution steps

2^{x + 1} + 2^{x - 1} = \frac{5}{2}

Factor

2^{x + 1} + 2^{x - 1} : 5 \cdot 2^{x - 1}

5 \cdot 2^{x - 1} = \frac{5}{2}

Divide both sides by

5

2^{x - 1} = \frac{1}{2}

Apply exponent rules

x - 1 = - 1

Solve

x - 1 = - 1 : x = 0

x = 0

4^{x + 1} = 256

3^{2 x} + 2 \times 3^{x + 1} = 16

3^{2 x} + 7 = 3^{x} + 1

\frac{9 ^{2 x}}{3 ^{x}} = 27

2^{x} + 2^{2 - x} - 5 = 0

What is the answer to 2^{x+1}+2^{x-1}= 5/2 ?
The answer to 2^{x+1}+2^{x-1}= 5/2 is x=0
Solve for x: 2^{x+1}+2^{x-1}= 5/2
The solution is x=0