What is the answer to sqrt(2^{3x-1)}=0.125 ?

The answer to sqrt(2^{3x-1)}=0.125 is x=-5/3

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sqrt(2^{3x-1)}=0.125

2^{3 x - 1} = 0.125

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

2^{3 x - 1} = 0.125

Apply exponent rules

(3 x - 1) \frac{1}{2} = - 3

Solve

(3 x - 1) \frac{1}{2} = - 3 : x = - \frac{5}{3}

x = - \frac{5}{3}

e^{e^{2 x}} = 3

2^{x} = 44

3 \times 3^{x} - 2 \times 3^{- x} = 1

3^{x^{2} + 1} = \frac{1}{9}

ln (4 e^{2 x}) = 1

What is the answer to sqrt(2^{3x-1)}=0.125 ?
The answer to sqrt(2^{3x-1)}=0.125 is x=-5/3
Solve for x: sqrt(2^{3x-1)}=0.125
The solution is x=-5/3