What is the answer to 4^{2x+3}=5^{x-2} ?

The answer to 4^{2x+3}=5^{x-2} is x=-(2ln(40))/(4ln(2)-ln(5))

Solve for x: 4^{2x+3}=5^{x-2}

The solution is x=-(2ln(40))/(4ln(2)-ln(5))

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4^{2 x + 3} = 5^{x - 2}

x = - \frac{2 ln ( 40 )}{4 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = - 6.34290 \dots

Solution steps

4^{2 x + 3} = 5^{x - 2}

Apply exponent rules

(2 x + 3) ln (4) = (x - 2) ln (5)

Solve

(2 x + 3) ln (4) = (x - 2) ln (5) : x = - \frac{2 ln ( 40 )}{4 ln ( 2 ) - ln ( 5 )}

x = - \frac{2 ln ( 40 )}{4 ln ( 2 ) - ln ( 5 )}

x, 5 e^{x} - 9 cos x = 2

2^{2 z - 2} + 2^{z + 2} = 48

1 - 2 e^{- 2 x} = 0

9^{x} + 3 = 28

y, e^{y} = x

What is the answer to 4^{2x+3}=5^{x-2} ?
The answer to 4^{2x+3}=5^{x-2} is x=-(2ln(40))/(4ln(2)-ln(5))
Solve for x: 4^{2x+3}=5^{x-2}
The solution is x=-(2ln(40))/(4ln(2)-ln(5))