What is the answer to solvefor x,e^{ax}=Ce^{bx} ?

The answer to solvefor x,e^{ax}=Ce^{bx} is x=(ln(C))/(a-b)

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solvefor x,e^{ax}=Ce^{bx}

solve for

x, e^{a x} = C e^{b x}

x = \frac{ln ( C )}{a - b}

Solution steps

e^{a x} = C e^{b x}

Apply exponent rules

a x = ln (C) + b x

Solve

a x = ln (C) + b x : x = \frac{ln ( C )}{a - b}

x = \frac{ln ( C )}{a - b}

e^{x + 7} = \frac{1}{e}

x, 2 = 5 e^{x} - 9 cos x

3^{x^{2}} = 7^{6 - x}

3^{l o g_{2} (x)} = 3^{5}

5^{2 x} - 6 \times 5^{x} + 5 = 0

What is the answer to solvefor x,e^{ax}=Ce^{bx} ?
The answer to solvefor x,e^{ax}=Ce^{bx} is x=(ln(C))/(a-b)