What is the answer to 9^x+3^{1+2x}=40 ?

The answer to 9^x+3^{1+2x}=40 is x=(ln(10))/(2ln(3))

Solve for x: 9^x+3^{1+2x}=40

The solution is x=(ln(10))/(2ln(3))

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9^{x} + 3^{1 + 2 x} = 40

x = \frac{ln ( 10 )}{2 ln ( 3 )}

Decimal Notation

x = 1.04795 \dots

Solution steps

9^{x} + 3^{1 + 2 x} = 40

Apply exponent rules

2 x ln (3) = ln (10)

Solve

2 x ln (3) = ln (10) : x = \frac{ln ( 10 )}{2 ln ( 3 )}

x = \frac{ln ( 10 )}{2 ln ( 3 )}

e^{2 x} + 3 e^{x} - 28 = 0

2 e^{2 x} = e^{x} + 10

2^{7 x} = 16384

2^{x x} = 2^{27}

4^{2 x + 1} = 3 2^{3 x}

What is the answer to 9^x+3^{1+2x}=40 ?
The answer to 9^x+3^{1+2x}=40 is x=(ln(10))/(2ln(3))
Solve for x: 9^x+3^{1+2x}=40
The solution is x=(ln(10))/(2ln(3))