What is the answer to 2^{x+1}+5\times 2^x=28 ?

The answer to 2^{x+1}+5\times 2^x=28 is x=2

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2^{x+1}+5\times 2^x=28

2^{x + 1} + 5 \cdot 2^{x} = 28

x = 2

Solution steps

2^{x + 1} + 5 \cdot 2^{x} = 28

Factor

2^{x + 1} + 5 \cdot 2^{x} : 7 \cdot 2^{x}

7 \cdot 2^{x} = 28

Divide both sides by

7

2^{x} = 4

Apply exponent rules

x = 2

7^{x} = 77

e^{2 x} - e^{x} - 20 = 0

400 = \frac{500}{1 + 4 e ^{0.5 t}}

3^{2 x + 2} - 10 \cdot 3^{x} + 1 = 0

1 6^{x - 9} = \frac{1}{2}

What is the answer to 2^{x+1}+5\times 2^x=28 ?
The answer to 2^{x+1}+5\times 2^x=28 is x=2
Solve for x: 2^{x+1}+5\times 2^x=28
The solution is x=2