What are the solutions to the equation 38(y+15)(y-17)=0 ?

The solutions to the equation 38(y+15)(y-17)=0 are y=-15,y=17

Find the zeros of 38(y+15)(y-17)=0

The zeros of 38(y+15)(y-17)=0 are y=-15,y=17

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38 (y + 15) (y - 17) = 0

y = - 15, y = 17

Solution steps

38 (y + 15) (y - 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 15 = 0 or y - 17 = 0

Solve

y + 15 = 0 : y = - 15

Solve

y - 17 = 0 : y = 17

The solutions to the quadratic equation are:

y = - 15, y = 17

x^{4} - y^{2}

∣ 3 a + 10 ∣ = ∣ 4 a - 8 ∣

2 x^{2} - 28 x + 96 = 0

∣ x + 4 ∣ = ∣ x - 5 ∣

∣ 2 x + 3 ∣ + ∣ x - 2 ∣ = 6 x

What are the solutions to the equation 38(y+15)(y-17)=0 ?
The solutions to the equation 38(y+15)(y-17)=0 are y=-15,y=17
Find the zeros of 38(y+15)(y-17)=0
The zeros of 38(y+15)(y-17)=0 are y=-15,y=17