What is the answer to 2^{6-3x}=8^{x+1} ?

The answer to 2^{6-3x}=8^{x+1} is x= 1/2

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2^{6-3x}=8^{x+1}

2^{6 - 3 x} = 8^{x + 1}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

2^{6 - 3 x} = 8^{x + 1}

Apply exponent rules

6 - 3 x = 3 (x + 1)

Solve

6 - 3 x = 3 (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

7^{x - 3} \times 98 = 14

2^{2 x} - 12 (2^{x}) + 35 = 0

1 0^{- 3 x} \cdot 1 0^{x} = \frac{1}{10}

e^{x + 1} = 1 0^{2 x}

e^{2 x + 1} = 11

What is the answer to 2^{6-3x}=8^{x+1} ?
The answer to 2^{6-3x}=8^{x+1} is x= 1/2
Solve for x: 2^{6-3x}=8^{x+1}
The solution is x= 1/2