What is the answer to 3^{x+2}=4^x ?

The answer to 3^{x+2}=4^x is x=(2ln(3))/(2ln(2)-ln(3))

Solve for x: 3^{x+2}=4^x

The solution is x=(2ln(3))/(2ln(2)-ln(3))

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3^{x + 2} = 4^{x}

x = \frac{2 ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 7.63768 \dots

Solution steps

3^{x + 2} = 4^{x}

Apply exponent rules

(x + 2) ln (3) = x ln (4)

Solve

(x + 2) ln (3) = x ln (4) : x = \frac{2 ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{2 ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

5^{x + 3} - 5^{x - 1} - 3120 = 0

1 0^{2 x - 3} = \frac{1}{10}

9^{3 x - 7} = 9^{5 - x}

ln (9 e^{2 x}) = 1

30 + 50 e^{- 0.2 x} = 40

What is the answer to 3^{x+2}=4^x ?
The answer to 3^{x+2}=4^x is x=(2ln(3))/(2ln(2)-ln(3))
Solve for x: 3^{x+2}=4^x
The solution is x=(2ln(3))/(2ln(2)-ln(3))