What is the answer to 3\times 4e^{2-2x}+1=4 ?

The answer to 3\times 4e^{2-2x}+1=4 is x=(2ln(2)+2)/2

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3\times 4e^{2-2x}+1=4

3 \cdot 4 e^{2 - 2 x} + 1 = 4

x = \frac{2 ln ( 2 ) + 2}{2}

Decimal Notation

x = 1.69314 \dots

Solution steps

3 \cdot 4 e^{2 - 2 x} + 1 = 4

Multiply the numbers:

3 \cdot 4 = 12

12 e^{2 - 2 x} + 1 = 4

Move

1

to the right side

12 e^{2 - 2 x} = 3

Divide both sides by

12

e^{2 - 2 x} = \frac{1}{4}

Apply exponent rules

2 - 2 x = ln (\frac{1}{4})

Solve

2 - 2 x = ln (\frac{1}{4}) : x = \frac{2 ln ( 2 ) + 2}{2}

x = \frac{2 ln ( 2 ) + 2}{2}

1 0^{\frac{x}{4}} = 3

e^{2 x} + 2 e^{2 x} x = 0

1000 e^{- 4 x} = 75

7^{x} - 7^{x - 1} = 6

0. 4^{x - 1} = 6.2 5^{6 x - 5}

What is the answer to 3\times 4e^{2-2x}+1=4 ?
The answer to 3\times 4e^{2-2x}+1=4 is x=(2ln(2)+2)/2