What is |6-(3d-5)|<= 14 ?

The solution to |6-(3d-5)|<= 14 is -1<= d<= 25/3

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|6-(3d-5)|<= 14

∣ 6 - (3 d - 5) ∣ \leq 14

- 1 \leq d \leq \frac{25}{3}

Interval Notation

[- 1, \frac{25}{3}]

Decimal Notation

- 1 \leq d \leq 8.33333 \dots

Solution steps

∣ 6 - (3 d - 5) ∣ \leq 14

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 14 \leq 6 - (3 d - 5) \leq 14

6 - (3 d - 5) \geq - 14 and 6 - (3 d - 5) \leq 14

d \leq \frac{25}{3} and d \geq - 1

Merge Overlapping Intervals

- 1 \leq d \leq \frac{25}{3}

8 m^{3} + 27

\frac{x}{28} = \frac{6}{7}

- 4 - 1

2 (x - 3)^{2} < 3

x^{2} - 6 x + 9 = 11