What is the answer to 2^{x-1}-2^{x+3}+2^x=-13/8 ?

The answer to 2^{x-1}-2^{x+3}+2^x=-13/8 is x=-2

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2^{x-1}-2^{x+3}+2^x=-13/8

2^{x - 1} - 2^{x + 3} + 2^{x} = - \frac{13}{8}

x = - 2

Solution steps

2^{x - 1} - 2^{x + 3} + 2^{x} = - \frac{13}{8}

Factor

2^{x - 1} - 2^{x + 3} + 2^{x} : - 13 \cdot 2^{x - 1}

- 13 \cdot 2^{x - 1} = - \frac{13}{8}

Divide both sides by

- 13

2^{x - 1} = \frac{1}{8}

Apply exponent rules

x - 1 = - 3

Solve

x - 1 = - 3 : x = - 2

x = - 2

3^{x} = 3 \frac{1}{4}

3 e^{- x} x^{2} - e^{- x} x^{3} = 0

8^{x + 3} = \frac{1}{16}

e^{x} = e^{x^{2} - 6}

3^{2 x - 1} = 2^{x + 3}

What is the answer to 2^{x-1}-2^{x+3}+2^x=-13/8 ?
The answer to 2^{x-1}-2^{x+3}+2^x=-13/8 is x=-2
Solve for x: 2^{x-1}-2^{x+3}+2^x=-13/8
The solution is x=-2