What is the answer to (1+x^2)2^x-5*2^x=0 ?

The answer to (1+x^2)2^x-5*2^x=0 is x=-2,x=2

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(1+x^2)2^x-5*2^x=0

(1 + x^{2}) 2^{x} - 5 \cdot 2^{x} = 0

x = - 2, x = 2

Solution steps

(1 + x^{2}) \cdot 2^{x} - 5 \cdot 2^{x} = 0

Factor

2^{x} (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} = 0 or x + 2 = 0 or x - 2 = 0

Solve

2^{x} = 0 :

No Solution for

x \in R

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

x = - 2, x = 2

t, 8000 = 245 t + 6125 e^{- 0.04 t}

4^{x} + 2^{x} = 12

x, 4^{2 x - 1} = 2^{x^{2} + 1}

8^{3 x - 5} = 3 2^{2 x + 3}

3 2^{x} = (\frac{1}{128})^{x - 8}

What is the answer to (1+x^2)2^x-5*2^x=0 ?
The answer to (1+x^2)2^x-5*2^x=0 is x=-2,x=2
Solve for x: (1+x^2)2^x-5*2^x=0
The solution is x=-2,x=2