What is the answer to 2^{x+2}+2^{x-1}=18 ?

The answer to 2^{x+2}+2^{x-1}=18 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+2}+2^{x-1}=18

2^{x + 2} + 2^{x - 1} = 18

x = 2

Solution steps

2^{x + 2} + 2^{x - 1} = 18

Factor

2^{x + 2} + 2^{x - 1} : 9 \cdot 2^{x - 1}

9 \cdot 2^{x - 1} = 18

Divide both sides by

9

2^{x - 1} = 2

Apply exponent rules

x - 1 = 1

Solve

x - 1 = 1 : x = 2

x = 2

2 \times 9^{x} = 54

2^{4 - 2 x} = 64

y, y^{x} = x^{y}

9^{x - 2} + 3^{x + 1} = 90

ln (5^{x} - 1) = 3

What is the answer to 2^{x+2}+2^{x-1}=18 ?
The answer to 2^{x+2}+2^{x-1}=18 is x=2
Solve for x: 2^{x+2}+2^{x-1}=18
The solution is x=2