What is the answer to 4^{3x}-1=8 ?

The answer to 4^{3x}-1=8 is x=(ln(3))/(3ln(2))

Solve for x: 4^{3x}-1=8

The solution is x=(ln(3))/(3ln(2))

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4^{3 x} - 1 = 8

x = \frac{ln ( 3 )}{3 ln ( 2 )}

Decimal Notation

x = 0.52832 \dots

Solution steps

4^{3 x} - 1 = 8

Move

1

to the right side

4^{3 x} = 9

Apply exponent rules

3 x ln (4) = ln (9)

Solve

3 x ln (4) = ln (9) : x = \frac{ln ( 3 )}{3 ln ( 2 )}

x = \frac{ln ( 3 )}{3 ln ( 2 )}

4^{x + 1} + 4^{x} = 160

5^{- x} = 3

3^{x} = 80

2 + e^{2 x} = 2 + 4 e^{- x}

2 e^{2 x} = e^{x} + 1

What is the answer to 4^{3x}-1=8 ?
The answer to 4^{3x}-1=8 is x=(ln(3))/(3ln(2))
Solve for x: 4^{3x}-1=8
The solution is x=(ln(3))/(3ln(2))