What is the answer to 7^{2x-3}=21 ?

The answer to 7^{2x-3}=21 is x=(ln(7203))/(2ln(7))

Solve for x: 7^{2x-3}=21

The solution is x=(ln(7203))/(2ln(7))

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7^{2 x - 3} = 21

x = \frac{ln ( 7203 )}{2 ln ( 7 )}

Decimal Notation

x = 2.28228 \dots

Solution steps

7^{2 x - 3} = 21

Apply exponent rules

(2 x - 3) ln (7) = ln (21)

Solve

(2 x - 3) ln (7) = ln (21) : x = \frac{ln ( 7203 )}{2 ln ( 7 )}

x = \frac{ln ( 7203 )}{2 ln ( 7 )}

5^{x - 3} = 25

3^{x + 2} + 9^{x - 1} = 90

7^{2 x + 3} + 42 \times 7^{x} - 1 = 0

3^{x^{2} - 4 x} = 4^{x^{2} - 4 x}

3^{2 x} + 2 \times 3^{x} - 15 = 0

What is the answer to 7^{2x-3}=21 ?
The answer to 7^{2x-3}=21 is x=(ln(7203))/(2ln(7))
Solve for x: 7^{2x-3}=21
The solution is x=(ln(7203))/(2ln(7))