What is the answer to 3^{2x+1}-5=11 ?

The answer to 3^{2x+1}-5=11 is x=(4ln(2)-ln(3))/(2ln(3))

Solve for x: 3^{2x+1}-5=11

The solution is x=(4ln(2)-ln(3))/(2ln(3))

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3^{2 x + 1} - 5 = 11

x = \frac{4 ln ( 2 ) - ln ( 3 )}{2 ln ( 3 )}

Decimal Notation

x = 0.76185 \dots

Solution steps

3^{2 x + 1} - 5 = 11

Move

5

to the right side

3^{2 x + 1} = 16

Apply exponent rules

(2 x + 1) ln (3) = ln (16)

Solve

(2 x + 1) ln (3) = ln (16) : x = \frac{4 ln ( 2 ) - ln ( 3 )}{2 ln ( 3 )}

x = \frac{4 ln ( 2 ) - ln ( 3 )}{2 ln ( 3 )}

2 5^{x} = \frac{1}{5}

1 6^{x} - 17 \times 4^{x} + 16 = 0

4 e^{x} = 91

2^{2 x} - 6 \times 2^{x} + 8 = 0

4^{x} \cdot 5^{4 x + 3} = 1 0^{2 x + 3}

What is the answer to 3^{2x+1}-5=11 ?
The answer to 3^{2x+1}-5=11 is x=(4ln(2)-ln(3))/(2ln(3))
Solve for x: 3^{2x+1}-5=11
The solution is x=(4ln(2)-ln(3))/(2ln(3))