What is the answer to 49*7^{3x}=5^x ?

The answer to 49*7^{3x}=5^x is x=-(2ln(7))/(3ln(7)-ln(5))

Solve for x: 49*7^{3x}=5^x

The solution is x=-(2ln(7))/(3ln(7)-ln(5))

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49 \cdot 7^{3 x} = 5^{x}

x = - \frac{2 ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = - 0.92042 \dots

Solution steps

49 \cdot 7^{3 x} = 5^{x}

Apply exponent rules

ln (49) + 3 x ln (7) = x ln (5)

Solve

ln (49) + 3 x ln (7) = x ln (5) : x = - \frac{2 ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

x = - \frac{2 ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

4^{x + 3} + 4^{x} = 260

8^{x + 2} = 4

2^{x + 1} + 2^{x - 1} + 2^{x} = 28

2 5^{x} + 5^{1 + 2 x} = 20

3^{2 x - 1} = 1

What is the answer to 49*7^{3x}=5^x ?
The answer to 49*7^{3x}=5^x is x=-(2ln(7))/(3ln(7)-ln(5))
Solve for x: 49*7^{3x}=5^x
The solution is x=-(2ln(7))/(3ln(7)-ln(5))