What is the answer to 18^{2x}*3^{-2x}=6 ?

The answer to 18^{2x}*3^{-2x}=6 is x= 1/2

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18^{2x}*3^{-2x}=6

1 8^{2 x} \cdot 3^{- 2 x} = 6

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

1 8^{2 x} \cdot 3^{- 2 x} = 6

Apply exponent rules

(lo g_{3} (18) \cdot 2 x - 2 x) ln (3) = ln (6)

Solve

(lo g_{3} (18) \cdot 2 x - 2 x) ln (3) = ln (6) : x = \frac{1}{2}

x = \frac{1}{2}

2^{- 3 n} \cdot \frac{1}{4} = 2^{n + 2}

e^{- x} = 0.5

(1.01 2^{t - 1998}) = 1.1707

2^{4 x - 2} = 4^{x + 2}

5^{3 x + 8} = 2 5^{2 x}

What is the answer to 18^{2x}*3^{-2x}=6 ?
The answer to 18^{2x}*3^{-2x}=6 is x= 1/2
Solve for x: 18^{2x}*3^{-2x}=6
The solution is x= 1/2