What is the answer to N(2018)=(2.7*10^{19})(1/2)^{2018/5370} ?

The answer to N(2018)=(2.7*10^{19})(1/2)^{2018/5370} is N=(5^{18}*1769472*2^{1676/2685})/(1009)

Solve for N: N(2018)=(2.7*10^{19})(1/2)^{2018/5370}

The solution is N=(5^{18}*1769472*2^{1676/2685})/(1009)

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N (2018) = (2.7 \cdot 1 0^{19}) (\frac{1}{2})^{\frac{2018}{5370}}

N = \frac{5 ^{18} \cdot 1769472 \cdot 2 ^{\frac{1676}{2685}}}{1009}

Decimal Notation

N = 1.03114 E 16

Solution steps

N (2018) = (2.7 \cdot 1 0^{19}) (\frac{1}{2})^{\frac{2018}{5370}}

Remove parentheses:

(a) = a

N (2018) = 2.7 \cdot 1 0^{19} (\frac{1}{2})^{\frac{2018}{5370}}

(\frac{1}{2})^{\frac{2018}{5370}} = (\frac{1}{2})^{\frac{1009}{2685}}

N (2018) = 1 0^{19} \cdot 2.7 (\frac{1}{2})^{\frac{1009}{2685}}

Multiply both sides by

10

20180 N = 1 0^{19} \cdot 27 (\frac{1}{2})^{\frac{1009}{2685}}

Divide both sides by

20180

N = \frac{5 ^{18} \cdot 1769472 \cdot 2 ^{\frac{1676}{2685}}}{1009}

24 x^{3} - 6 x^{2} + 8 x - 2

\frac{3 - i}{- 6 i}

x^{2} - 13 x + 4 = - 6 x - 2

\frac{x}{x - 7} > 0

m^{2} + 9 m + 18

What is the answer to N(2018)=(2.7*10^{19})(1/2)^{2018/5370} ?
The answer to N(2018)=(2.7*10^{19})(1/2)^{2018/5370} is N=(5^{18}*1769472*2^{1676/2685})/(1009)
Solve for N: N(2018)=(2.7*10^{19})(1/2)^{2018/5370}
The solution is N=(5^{18}*1769472*2^{1676/2685})/(1009)