What is the answer to 5^x=6^{x-1} ?

The answer to 5^x=6^{x-1} is x=(ln(6))/(ln(6)-ln(5))

Solve for x: 5^x=6^{x-1}

The solution is x=(ln(6))/(ln(6)-ln(5))

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5^{x} = 6^{x - 1}

x = \frac{ln ( 6 )}{ln ( 6 ) - ln ( 5 )}

Solution steps

5^{x} = 6^{x - 1}

Apply exponent rules

x ln (5) = (x - 1) ln (6)

Solve

x ln (5) = (x - 1) ln (6) : x = \frac{ln ( 6 )}{ln ( 6 ) - ln ( 5 )}

x = \frac{ln ( 6 )}{ln ( 6 ) - ln ( 5 )}

3 e^{2 x} - 4 e^{- 2 x} = 5

2^{x^{2} - 3} = \frac{1}{4}

e^{x + 1} = 2

5^{x} = - 125

ln (\frac{e ^{2 x}}{4}) = 1

What is the answer to 5^x=6^{x-1} ?
The answer to 5^x=6^{x-1} is x=(ln(6))/(ln(6)-ln(5))
Solve for x: 5^x=6^{x-1}
The solution is x=(ln(6))/(ln(6)-ln(5))