What is the answer to 7^{3x-4}=3^{x-5} ?

The answer to 7^{3x-4}=3^{x-5} is x=(-5ln(3)+4ln(7))/(3ln(7)-ln(3))

Solve for x: 7^{3x-4}=3^{x-5}

The solution is x=(-5ln(3)+4ln(7))/(3ln(7)-ln(3))

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7^{3 x - 4} = 3^{x - 5}

x = \frac{- 5 ln ( 3 ) + 4 ln ( 7 )}{3 ln ( 7 ) - ln ( 3 )}

Solution steps

7^{3 x - 4} = 3^{x - 5}

Apply exponent rules

(3 x - 4) ln (7) = (x - 5) ln (3)

Solve

(3 x - 4) ln (7) = (x - 5) ln (3) : x = \frac{- 5 ln ( 3 ) + 4 ln ( 7 )}{3 ln ( 7 ) - ln ( 3 )}

x = \frac{- 5 ln ( 3 ) + 4 ln ( 7 )}{3 ln ( 7 ) - ln ( 3 )}

- 2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2}) = 0

0 = - e^{- x} + 3 e^{- 3 x}

2^{\frac{x}{15}} = 10

x = e^{\frac{( x l n ( 2 ) )}{2}}

4 9^{x} \cdot 7^{x^{2}} = 240 1^{2}

What is the answer to 7^{3x-4}=3^{x-5} ?
The answer to 7^{3x-4}=3^{x-5} is x=(-5ln(3)+4ln(7))/(3ln(7)-ln(3))
Solve for x: 7^{3x-4}=3^{x-5}
The solution is x=(-5ln(3)+4ln(7))/(3ln(7)-ln(3))