What is the answer to solvefor x,e^{xy}-y^2=e-4 ?

The answer to solvefor x,e^{xy}-y^2=e-4 is x=(ln(e-4+y^2))/y

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solvefor x,e^{xy}-y^2=e-4

solve for

x, e^{x y} - y^{2} = e - 4

x = \frac{ln ( e - 4 + y ^{2} )}{y}

Solution steps

e^{x y} - y^{2} = e - 4

Move

y^{2}

to the right side

e^{x y} = e - 4 + y^{2}

Apply exponent rules

x y = ln (e - 4 + y^{2})

Solve

x y = ln (e - 4 + y^{2}) : x = \frac{ln ( e - 4 + y ^{2} )}{y}

x = \frac{ln ( e - 4 + y ^{2} )}{y}

10 e^{\frac{x}{2}} = 1

3^{2 x - 6} = 81

2^{2 x + 3} = 15

3^{x} + 3^{x + 1} = 4

e^{x} = e^{2 x}

What is the answer to solvefor x,e^{xy}-y^2=e-4 ?
The answer to solvefor x,e^{xy}-y^2=e-4 is x=(ln(e-4+y^2))/y