What is the answer to 4^{x+2}\times 4^x=120 ?

The answer to 4^{x+2}\times 4^x=120 is x=(ln(15/2))/(4ln(2))

Solve for x: 4^{x+2}\times 4^x=120

The solution is x=(ln(15/2))/(4ln(2))

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4^{x + 2} \cdot 4^{x} = 120

x = \frac{ln ( \frac{15}{2} )}{4 ln ( 2 )}

Decimal Notation

x = 0.72672 \dots

Solution steps

4^{x + 2} \cdot 4^{x} = 120

Apply exponent rules

(x + 2 + x) ln (4) = ln (120)

Solve

(x + 2 + x) ln (4) = ln (120) : x = \frac{ln ( \frac{15}{2} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{15}{2} )}{4 ln ( 2 )}

9^{x} - 8 (3^{x}) + 15 = 0

40 + 30 e^{- 0.2 x} = 50

5 e^{5 x} - e^{- x} = 0

2 (1.24)^{x} + 1 = 14

e^{x} + 2 = 3 e^{- x}

What is the answer to 4^{x+2}\times 4^x=120 ?
The answer to 4^{x+2}\times 4^x=120 is x=(ln(15/2))/(4ln(2))
Solve for x: 4^{x+2}\times 4^x=120
The solution is x=(ln(15/2))/(4ln(2))