What is the answer to (2^{4x-1})/(2^{3x+2)}=16 ?

The answer to (2^{4x-1})/(2^{3x+2)}=16 is x=7

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(2^{4x-1})/(2^{3x+2)}=16

\frac{2 ^{4 x - 1}}{2 ^{3 x + 2}} = 16

x = 7

Solution steps

\frac{2 ^{4 x - 1}}{2 ^{3 x + 2}} = 16

Apply exponent rules

x - 3 = 4

Solve

x - 3 = 4 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

3^{x - 1} - 3^{x} + 3^{x + 1} = 63

5^{9 x - 12} = 2 5^{x}

2^{x - 4} = 3 2^{4}

6^{2 x} + 6^{x} - 12 = 0

500 e^{- 2 x} = 125

What is the answer to (2^{4x-1})/(2^{3x+2)}=16 ?
The answer to (2^{4x-1})/(2^{3x+2)}=16 is x=7
Solve for x: (2^{4x-1})/(2^{3x+2)}=16
The solution is x=7