What is the answer to 5^{3x+4}=(5x)/(25) ?

The answer to 5^{3x+4}=(5x)/(25) is No Solution for x\in\mathbb{R}

Solve for x: 5^{3x+4}=(5x)/(25)

The solution is No Solution for x\in\mathbb{R}

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5^{3 x + 4} = \frac{5 x}{25}

No Solution for x \in R

Solution steps

5^{3 x + 4} = \frac{5 x}{25}

Prepare

5^{3 x + 4} = \frac{5 x}{25}

for Lambert form:

25 = e^{l n (5) (- 3 x - 3)} x

Rewrite the equation with

- 3 x ln (5) = u

and

x = - \frac{u}{3 ln ( 5 )}

25 = e^{l n (5) (- 3 (- \frac{u}{3 l n ( 5 )}) - 3)} (- \frac{u}{3 ln ( 5 )})

Simplify

25 = - \frac{e ^{u - 3 l n (5)} u}{3 ln ( 5 )}

Rewrite

25 = - \frac{e ^{u - 3 l n (5)} u}{3 ln ( 5 )}

in Lambert form:

e^{u} u = - 9375 ln (5)

Solve

e^{u} u = - 9375 ln (5) :

No Solution for

u \in R

No Solution for x \in R

e^{x}

8 \times 2^{x} = 4

2 5^{x - 3} - \frac{1}{5} = 0

5^{x + 1} + 5^{x - 1} = 130

5^{2 x + 3} = 3^{x - 1}

What is the answer to 5^{3x+4}=(5x)/(25) ?
The answer to 5^{3x+4}=(5x)/(25) is No Solution for x\in\mathbb{R}
Solve for x: 5^{3x+4}=(5x)/(25)
The solution is No Solution for x\in\mathbb{R}