What is the answer to 3^{2x}(3^{2x-1})^3=9 ?

The answer to 3^{2x}(3^{2x-1})^3=9 is x= 5/8

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3^{2x}(3^{2x-1})^3=9

3^{2 x} (3^{2 x - 1})^{3} = 9

x = \frac{5}{8}

Solution steps

3^{2 x} (3^{2 x - 1})^{3} = 9

Apply exponent rules

2 x + (2 x - 1) \cdot 3 = 2

Solve

2 x + (2 x - 1) \cdot 3 = 2 : x = \frac{5}{8}

x = \frac{5}{8}

e^{- x} x^{4} - 8 e^{- x} x^{3} + 12 e^{- x} x^{2} = 0

3^{x} = 5^{2 x}

x, 9^{5 + 2 z} = x

4^{5 x - 2} = 3^{- 2 x + 1}

4 \cdot e^{3 x - 2} = 66

What is the answer to 3^{2x}(3^{2x-1})^3=9 ?
The answer to 3^{2x}(3^{2x-1})^3=9 is x= 5/8
Solve for x: 3^{2x}(3^{2x-1})^3=9
The solution is x= 5/8