What are the solutions to the equation 4x^2-16=0 ?

The solutions to the equation 4x^2-16=0 are x=2,x=-2

Find the zeros of 4x^2-16=0

The zeros of 4x^2-16=0 are x=2,x=-2

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4 x^{2} - 16 = 0

x = 2, x = - 2

Solution steps

4 x^{2} - 16 = 0

Move

16

to the right side

4 x^{2} = 16

Divide both sides by

4

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

\frac{0 ^{2} - 25}{0 - 5}

s^{2} + 3 s - 10

3 (0) + 9 (- 2) < - 18

\frac{4 \cdot 1 0 ^{- 12}}{6 \cdot 1 0 ^{4}}

6 x^{2} + 5 x y - 6 y^{2}

What are the solutions to the equation 4x^2-16=0 ?
The solutions to the equation 4x^2-16=0 are x=2,x=-2
Find the zeros of 4x^2-16=0
The zeros of 4x^2-16=0 are x=2,x=-2