What is the answer to 10^{x/5}=57 ?

The answer to 10^{x/5}=57 is x=(5ln(57))/(ln(10))

Solve for x: 10^{x/5}=57

The solution is x=(5ln(57))/(ln(10))

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1 0^{\frac{x}{5}} = 57

x = \frac{5 ln ( 57 )}{ln ( 10 )}

Solution steps

1 0^{\frac{x}{5}} = 57

Apply exponent rules

\frac{x}{5} ln (10) = ln (57)

Solve

\frac{x}{5} ln (10) = ln (57) : x = \frac{5 ln ( 57 )}{ln ( 10 )}

x = \frac{5 ln ( 57 )}{ln ( 10 )}

e^{x} - 2 e^{- 2 x} = 0

40 0^{x} = \frac{1}{20}

1 0^{\frac{x}{2}} = 83

e^{x + 2} = \frac{1}{e}

9^{- 3 x + 2} = 48

What is the answer to 10^{x/5}=57 ?
The answer to 10^{x/5}=57 is x=(5ln(57))/(ln(10))
Solve for x: 10^{x/5}=57
The solution is x=(5ln(57))/(ln(10))