What is the answer to 6(2^{3x-1})-7=9 ?

The answer to 6(2^{3x-1})-7=9 is x=(ln(16/3))/(3ln(2))

Solve for x: 6(2^{3x-1})-7=9

The solution is x=(ln(16/3))/(3ln(2))

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6 (2^{3 x - 1}) - 7 = 9

x = \frac{ln ( \frac{16}{3} )}{3 ln ( 2 )}

Decimal Notation

x = 0.80501 \dots

Solution steps

6 (2^{3 x - 1}) - 7 = 9

Move

7

to the right side

6 \cdot 2^{3 x - 1} = 16

Divide both sides by

6

2^{3 x - 1} = \frac{8}{3}

Apply exponent rules

(3 x - 1) ln (2) = ln (\frac{8}{3})

Solve

(3 x - 1) ln (2) = ln (\frac{8}{3}) : x = \frac{ln ( \frac{16}{3} )}{3 ln ( 2 )}

x = \frac{ln ( \frac{16}{3} )}{3 ln ( 2 )}

3^{x + 2} - 5 \times 3^{x} = 36

e^{7 x} = 2

e^{7 x} = 6

4^{x - 3} = 9

e^{2 x} - 10 e^{- 2 x} = 0

What is the answer to 6(2^{3x-1})-7=9 ?
The answer to 6(2^{3x-1})-7=9 is x=(ln(16/3))/(3ln(2))
Solve for x: 6(2^{3x-1})-7=9
The solution is x=(ln(16/3))/(3ln(2))