What is the answer to 10^{1-2x}=11 ?

The answer to 10^{1-2x}=11 is x=-(ln(11)-ln(10))/(2ln(10))

Solve for x: 10^{1-2x}=11

The solution is x=-(ln(11)-ln(10))/(2ln(10))

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1 0^{1 - 2 x} = 11

x = - \frac{ln ( 11 ) - ln ( 10 )}{2 ln ( 10 )}

Decimal Notation

x = - 0.02069 \dots

Solution steps

1 0^{1 - 2 x} = 11

Apply exponent rules

(1 - 2 x) ln (10) = ln (11)

Solve

(1 - 2 x) ln (10) = ln (11) : x = - \frac{ln ( 11 ) - ln ( 10 )}{2 ln ( 10 )}

x = - \frac{ln ( 11 ) - ln ( 10 )}{2 ln ( 10 )}

6 4^{x} = 128

\frac{e ^{x}}{1 + e ^{x}} = 0.9

y, \frac{3 ^{y + 1}}{32} = 9 6^{x}

3^{3 x + 2} = 3

y, x = \frac{1 + e ^{y}}{1 - e ^{y}}

What is the answer to 10^{1-2x}=11 ?
The answer to 10^{1-2x}=11 is x=-(ln(11)-ln(10))/(2ln(10))
Solve for x: 10^{1-2x}=11
The solution is x=-(ln(11)-ln(10))/(2ln(10))