What is the answer to 9^x-4\times 3^x+3=0 ?

The answer to 9^x-4\times 3^x+3=0 is x=1,x=0

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9^x-4\times 3^x+3=0

9^{x} - 4 \cdot 3^{x} + 3 = 0

x = 1, x = 0

Solution steps

9^{x} - 4 \cdot 3^{x} + 3 = 0

Apply exponent rules

(3^{x})^{2} - 4 \cdot 3^{x} + 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 4 u + 3 = 0

Solve

u^{2} - 4 u + 3 = 0 : u = 3, u = 1

u = 3, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = 1 : x = 0

x = 1, x = 0

\frac{1000}{1 + 39 e ^{- 0.42 x}} = 630

3 = e^{2 x}

5 = a \times b^{- (x - c)} + d

1 6^{3 x - 2} = 3 2^{x + 4}

9^{x} - 2 \times 3^{x + 2} + 81 = 0

What is the answer to 9^x-4\times 3^x+3=0 ?
The answer to 9^x-4\times 3^x+3=0 is x=1,x=0
Solve for x: 9^x-4\times 3^x+3=0
The solution is x=1,x=0