What is the answer to 3\times 2^{x+2}-5\times 2^{x-1}=76 ?

The answer to 3\times 2^{x+2}-5\times 2^{x-1}=76 is x=3

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3\times 2^{x+2}-5\times 2^{x-1}=76

3 \cdot 2^{x + 2} - 5 \cdot 2^{x - 1} = 76

x = 3

Solution steps

3 \cdot 2^{x + 2} - 5 \cdot 2^{x - 1} = 76

Factor

3 \cdot 2^{x + 2} - 5 \cdot 2^{x - 1} : 19 \cdot 2^{x - 1}

19 \cdot 2^{x - 1} = 76

Divide both sides by

19

2^{x - 1} = 4

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

B = 200 e^{0.7 t}

e^{k x}

e^{n x}

x^{2 + l o g_{10} (10 x)} = 10000

\frac{( \frac{1}{5} ) ^{3 x}}{2 5 ^{2 + x}} = 5

What is the answer to 3\times 2^{x+2}-5\times 2^{x-1}=76 ?
The answer to 3\times 2^{x+2}-5\times 2^{x-1}=76 is x=3
Solve for x: 3\times 2^{x+2}-5\times 2^{x-1}=76
The solution is x=3