What is the answer to 2^{x^2}\times 4^x\times 2=4 ?

The answer to 2^{x^2}\times 4^x\times 2=4 is x=-1+sqrt(2),x=-1-sqrt(2)

Solve for x: 2^{x^2}\times 4^x\times 2=4

The solution is x=-1+sqrt(2),x=-1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x^{2}} \cdot 4^{x} \cdot 2 = 4

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

2^{x^{2}} \cdot 4^{x} \cdot 2 = 4

Apply exponent rules

x^{2} + 1 + 2 x = 2

Solve

x^{2} + 1 + 2 x = 2 : x = - 1 + 2, x = - 1 - 2

x = - 1 + 2, x = - 1 - 2

\frac{500}{100 - e ^{\frac{x}{2}}} = 20

7^{x + 2} = 5764801

3^{2 x} = 4^{(x + 1)}

15 = 17 e^{- (0.116) t}

2^{x + 1} + 2^{x - 2} = \frac{9}{2}

What is the answer to 2^{x^2}\times 4^x\times 2=4 ?
The answer to 2^{x^2}\times 4^x\times 2=4 is x=-1+sqrt(2),x=-1-sqrt(2)
Solve for x: 2^{x^2}\times 4^x\times 2=4
The solution is x=-1+sqrt(2),x=-1-sqrt(2)