What is the answer to 3^{x+1}+3^x+3^{x+1}=39 ?

The answer to 3^{x+1}+3^x+3^{x+1}=39 is x=(ln(39/7))/(ln(3))

Solve for x: 3^{x+1}+3^x+3^{x+1}=39

The solution is x=(ln(39/7))/(ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{x + 1} + 3^{x} + 3^{x + 1} = 39

x = \frac{ln ( \frac{39}{7} )}{ln ( 3 )}

Decimal Notation

x = 1.56347 \dots

Solution steps

3^{x + 1} + 3^{x} + 3^{x + 1} = 39

Factor

3^{x + 1} + 3^{x} + 3^{x + 1} : 7 \cdot 3^{x}

7 \cdot 3^{x} = 39

Divide both sides by

7

3^{x} = \frac{39}{7}

Apply exponent rules

x ln (3) = ln (\frac{39}{7})

Solve

x ln (3) = ln (\frac{39}{7}) : x = \frac{ln ( \frac{39}{7} )}{ln ( 3 )}

x = \frac{ln ( \frac{39}{7} )}{ln ( 3 )}

3^{\frac{x}{3}} = 99

5^{x} = 44

3^{3 x} = 3

2^{\frac{x}{4}} = 9

- x e^{- x} + 8 e^{- x} = 0

What is the answer to 3^{x+1}+3^x+3^{x+1}=39 ?
The answer to 3^{x+1}+3^x+3^{x+1}=39 is x=(ln(39/7))/(ln(3))
Solve for x: 3^{x+1}+3^x+3^{x+1}=39
The solution is x=(ln(39/7))/(ln(3))