What is the answer to 4^{x+1}+4^{x+2}=320 ?

The answer to 4^{x+1}+4^{x+2}=320 is x=2

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4^{x+1}+4^{x+2}=320

4^{x + 1} + 4^{x + 2} = 320

x = 2

Solution steps

4^{x + 1} + 4^{x + 2} = 320

Factor

4^{x + 1} + 4^{x + 2} : 5 \cdot 4^{x + 1}

5 \cdot 4^{x + 1} = 320

Divide both sides by

5

4^{x + 1} = 64

Apply exponent rules

x + 1 = 3

Solve

x + 1 = 3 : x = 2

x = 2

6 4^{x - 4} = 1 6^{x - 3}

3^{2 x} - 3^{x - 1} = 3^{x + 1} - 1

3^{2 x - 7} = 27

2^{x^{3}} = 3 2^{x}

2 \cdot 3^{x} = 7 \cdot 5^{x}

What is the answer to 4^{x+1}+4^{x+2}=320 ?
The answer to 4^{x+1}+4^{x+2}=320 is x=2
Solve for x: 4^{x+1}+4^{x+2}=320
The solution is x=2