What is the answer to 3^{-2x+1}*3^{-2x-3}=3^{-x} ?

The answer to 3^{-2x+1}*3^{-2x-3}=3^{-x} is x=-2/3

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3^{-2x+1}*3^{-2x-3}=3^{-x}

3^{- 2 x + 1} \cdot 3^{- 2 x - 3} = 3^{- x}

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

3^{- 2 x + 1} \cdot 3^{- 2 x - 3} = 3^{- x}

Apply exponent rules

- 4 x - 2 = - x

Solve

- 4 x - 2 = - x : x = - \frac{2}{3}

x = - \frac{2}{3}

e^{x} + \frac{1}{2} = 0

2^{x - 2} = 64

1.14 (1.0134)^{x} = 4.23

7^{2 x} + 7^{x} - 12 = 0

y, y = e^{x + y}

What is the answer to 3^{-2x+1}*3^{-2x-3}=3^{-x} ?
The answer to 3^{-2x+1}*3^{-2x-3}=3^{-x} is x=-2/3
Solve for x: 3^{-2x+1}*3^{-2x-3}=3^{-x}
The solution is x=-2/3