What is the answer to 2^{4x+1}\times 8^{-x+3}= 1/16 ?

The answer to 2^{4x+1}\times 8^{-x+3}= 1/16 is x=-14

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2^{4x+1}\times 8^{-x+3}= 1/16

2^{4 x + 1} \cdot 8^{- x + 3} = \frac{1}{16}

x = - 14

Solution steps

2^{4 x + 1} \cdot 8^{- x + 3} = \frac{1}{16}

Apply exponent rules

4 x + 1 + 3 (- x + 3) = - 4

Solve

4 x + 1 + 3 (- x + 3) = - 4 : x = - 14

x = - 14

2^{x + 1} + 2^{x} + 2^{x - 1} = 7

e^{\frac{x}{2}} = 2 e^{2 x}

e^{x + 1} = 6^{x + 6}

e^{x^{2} + 6} = e^{5 x}

1 5^{x - 11} = 1 1^{x}

What is the answer to 2^{4x+1}\times 8^{-x+3}= 1/16 ?
The answer to 2^{4x+1}\times 8^{-x+3}= 1/16 is x=-14
Solve for x: 2^{4x+1}\times 8^{-x+3}= 1/16
The solution is x=-14