What is the answer to 25^x+5^{1+2x}=40 ?

The answer to 25^x+5^{1+2x}=40 is x=(ln(20/3))/(2ln(5))

Solve for x: 25^x+5^{1+2x}=40

The solution is x=(ln(20/3))/(2ln(5))

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2 5^{x} + 5^{1 + 2 x} = 40

x = \frac{ln ( \frac{20}{3} )}{2 ln ( 5 )}

Decimal Notation

x = 0.58937 \dots

Solution steps

2 5^{x} + 5^{1 + 2 x} = 40

Apply exponent rules

2 x ln (5) = ln (\frac{20}{3})

Solve

2 x ln (5) = ln (\frac{20}{3}) : x = \frac{ln ( \frac{20}{3} )}{2 ln ( 5 )}

x = \frac{ln ( \frac{20}{3} )}{2 ln ( 5 )}

x, 3^{x + 1} = 3^{x} + 18

3^{2 x - 1} = 3

5 (1 0^{2 x} - 2) = 15

5^{n + 10} = 25

e^{- 9 x} = 0

What is the answer to 25^x+5^{1+2x}=40 ?
The answer to 25^x+5^{1+2x}=40 is x=(ln(20/3))/(2ln(5))
Solve for x: 25^x+5^{1+2x}=40
The solution is x=(ln(20/3))/(2ln(5))