What is the answer to 3^{2+x}=172 ?

The answer to 3^{2+x}=172 is x=(ln(172))/(ln(3))-2

Solve for x: 3^{2+x}=172

The solution is x=(ln(172))/(ln(3))-2

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3^{2 + x} = 172

x = \frac{ln ( 172 )}{ln ( 3 )} - 2

Decimal Notation

x = 2.68545 \dots

Solution steps

3^{2 + x} = 172

Apply exponent rules

(2 + x) ln (3) = ln (172)

Solve

(2 + x) ln (3) = ln (172) : x = \frac{ln ( 172 )}{ln ( 3 )} - 2

x = \frac{ln ( 172 )}{ln ( 3 )} - 2

5^{x - 1} = 2^{2 x + 1}

3^{- 5} \cdot 3^{3} = 3^{k}

11 \cdot 1 0^{x - 3} - 1 0^{2 x - 4} = 0.1

5^{2 x} 3 = 75

x e^{x} - 7 x e^{x} = 0

What is the answer to 3^{2+x}=172 ?
The answer to 3^{2+x}=172 is x=(ln(172))/(ln(3))-2
Solve for x: 3^{2+x}=172
The solution is x=(ln(172))/(ln(3))-2